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![Simon Glass](/assets/img/avatar_default.png)
This code generates lots of checkpatch errors. Fix them. Signed-off-by: Simon Glass <sjg@chromium.org> Reviewed-by: Bin Meng <bmeng.cn@gmail.com>
144 lines
3.5 KiB
C
144 lines
3.5 KiB
C
/*
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* (C) Copyright 2001
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* Wolfgang Denk, DENX Software Engineering, wd@denx.de.
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*
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* SPDX-License-Identifier: GPL-2.0+
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*/
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#include <common.h>
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#include <command.h>
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#include <errno.h>
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#include <rtc.h>
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#if defined(CONFIG_CMD_DATE) || defined(CONFIG_TIMESTAMP)
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#define FEBRUARY 2
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#define STARTOFTIME 1970
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#define SECDAY 86400L
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#define SECYR (SECDAY * 365)
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#define leapyear(year) ((year) % 4 == 0)
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#define days_in_year(a) (leapyear(a) ? 366 : 365)
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#define days_in_month(a) (month_days[(a) - 1])
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static int month_days[12] = {
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31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31
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};
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static int month_offset[] = {
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0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334
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};
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/*
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* This only works for the Gregorian calendar - i.e. after 1752 (in the UK)
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*/
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int rtc_calc_weekday(struct rtc_time *tm)
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{
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int leaps_to_date;
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int last_year;
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int day;
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if (tm->tm_year < 1753)
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return -1;
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last_year = tm->tm_year - 1;
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/* Number of leap corrections to apply up to end of last year */
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leaps_to_date = last_year / 4 - last_year / 100 + last_year / 400;
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/*
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* This year is a leap year if it is divisible by 4 except when it is
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* divisible by 100 unless it is divisible by 400
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*
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* e.g. 1904 was a leap year, 1900 was not, 1996 is, and 2000 is.
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*/
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if (tm->tm_year % 4 == 0 &&
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((tm->tm_year % 100 != 0) || (tm->tm_year % 400 == 0)) &&
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tm->tm_mon > 2) {
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/* We are past Feb. 29 in a leap year */
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day = 1;
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} else {
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day = 0;
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}
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day += last_year * 365 + leaps_to_date + month_offset[tm->tm_mon - 1] +
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tm->tm_mday;
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tm->tm_wday = day % 7;
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return 0;
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}
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int rtc_to_tm(int tim, struct rtc_time *tm)
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{
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register int i;
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register long hms, day;
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day = tim / SECDAY;
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hms = tim % SECDAY;
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/* Hours, minutes, seconds are easy */
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tm->tm_hour = hms / 3600;
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tm->tm_min = (hms % 3600) / 60;
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tm->tm_sec = (hms % 3600) % 60;
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/* Number of years in days */
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for (i = STARTOFTIME; day >= days_in_year(i); i++)
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day -= days_in_year(i);
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tm->tm_year = i;
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/* Number of months in days left */
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if (leapyear(tm->tm_year))
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days_in_month(FEBRUARY) = 29;
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for (i = 1; day >= days_in_month(i); i++)
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day -= days_in_month(i);
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days_in_month(FEBRUARY) = 28;
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tm->tm_mon = i;
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/* Days are what is left over (+1) from all that */
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tm->tm_mday = day + 1;
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/* Zero unused fields */
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tm->tm_yday = 0;
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tm->tm_isdst = 0;
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/*
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* Determine the day of week
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*/
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return rtc_calc_weekday(tm);
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}
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/*
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* Converts Gregorian date to seconds since 1970-01-01 00:00:00.
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* Assumes input in normal date format, i.e. 1980-12-31 23:59:59
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* => year=1980, mon=12, day=31, hour=23, min=59, sec=59.
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*
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* [For the Julian calendar (which was used in Russia before 1917,
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* Britain & colonies before 1752, anywhere else before 1582,
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* and is still in use by some communities) leave out the
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* -year / 100 + year / 400 terms, and add 10.]
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*
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* This algorithm was first published by Gauss (I think).
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*
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* WARNING: this function will overflow on 2106-02-07 06:28:16 on
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* machines where long is 32-bit! (However, as time_t is signed, we
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* will already get problems at other places on 2038-01-19 03:14:08)
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*/
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unsigned long rtc_mktime(const struct rtc_time *tm)
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{
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int mon = tm->tm_mon;
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int year = tm->tm_year;
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int days, hours;
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mon -= 2;
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if (0 >= (int)mon) { /* 1..12 -> 11, 12, 1..10 */
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mon += 12; /* Puts Feb last since it has leap day */
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year -= 1;
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}
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days = (unsigned long)(year / 4 - year / 100 + year / 400 +
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367 * mon / 12 + tm->tm_mday) +
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year * 365 - 719499;
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hours = days * 24 + tm->tm_hour;
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return (hours * 60 + tm->tm_min) * 60 + tm->tm_sec;
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}
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#endif
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