Stephen Warren 58e22f8a15 fdt: send all dtc output to stderr ... Commit 896bbb5 "fdt: avoid bad MAKEALL status" added logic to capture the result code from dtc by echoing $? to stdout and capturing it using $(). However, dtc emits some diagnostics to stderr and some to stdout. The diagnostics send to stdout ended up getting captured via $() rather than being echo'd to the user. This caused those diagnostics to be passed to the exit command, which would then fail with the following cryptic error message: /bin/sh: line 1: exit: too many arguments Solve this by redirecting all dtc output to stderr so that $() does not capture it. This allows the user to see the actual error message from dtc. Cc: Wolfgang Denk <wd@denx.de> Cc: Simon Glass <sjg@chromium.org> Cc: albert.u.boot@aribaud.net Cc: Tom Warren <twarren@nvidia.com> Signed-off-by: Stephen Warren <swarren@nvidia.com> Acked-by: Simon Glass <sjg@chromium.org>		2012-07-09 09:05:24 +02:00
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Makefile	fdt: send all dtc output to stderr	2012-07-09 09:05:24 +02:00