brain-hackers_pepepper-mirror
/
linux-brain
mirror of https://github.com/brain-hackers/linux-brain.git
1
0
Fork 0
Code Issues Projects Releases Wiki Activity

blok, bfq: do not plug I/O if all queues are weight-raised 

[ Upstream commit c8765de0ad ]

To reduce latency for interactive and soft real-time applications, bfq
privileges the bfq_queues containing the I/O of these
applications. These privileged queues, referred-to as weight-raised
queues, get a much higher share of the device throughput
w.r.t. non-privileged queues. To preserve this higher share, the I/O
of any non-weight-raised queue must be plugged whenever a sync
weight-raised queue, while being served, remains temporarily empty. To
attain this goal, bfq simply plugs any I/O (from any queue), if a sync
weight-raised queue remains empty while in service.

Unfortunately, this plugging typically lowers throughput with random
I/O, on devices with internal queueing (because it reduces the filling
level of the internal queues of the device).

This commit addresses this issue by restricting the cases where
plugging is performed: if a sync weight-raised queue remains empty
while in service, then I/O plugging is performed only if some of the
active bfq_queues are *not* weight-raised (which is actually the only
circumstance where plugging is needed to preserve the higher share of
the throughput of weight-raised queues). This restriction proved able
to boost throughput in really many use cases needing only maximum
throughput.

Signed-off-by: Paolo Valente <paolo.valente@linaro.org>
Signed-off-by: Jens Axboe <axboe@kernel.dk>
Signed-off-by: Sasha Levin <sashal@kernel.org>
This commit is contained in:
Paolo Valente 2018-09-14 16:23:09 +02:00 committed by Greg Kroah-Hartman
parent e269eb6f1f
commit f927911d4a
1 changed files with 8 additions and 2 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

10
block/bfq-iosched.c
View File

@ -3314,7 +3314,12 @@ static bool bfq_bfqq_may_idle(struct bfq_queue *bfqq)
* whether bfqq is being weight-raised, because
* bfq_symmetric_scenario() does not take into account also
* weight-raised queues (see comments on
* bfq_weights_tree_add()).
* bfq_weights_tree_add()). In particular, if bfqq is being
* weight-raised, it is important to idle only if there are
* other, non-weight-raised queues that may steal throughput
* to bfqq. Actually, we should be even more precise, and
* differentiate between interactive weight raising and
* soft real-time weight raising.
*
* As a side note, it is worth considering that the above
* device-idling countermeasures may however fail in the
@ -3326,7 +3331,8 @@ static bool bfq_bfqq_may_idle(struct bfq_queue *bfqq)
* to let requests be served in the desired order until all
* the requests already queued in the device have been served.
*/
asymmetric_scenario = bfqq->wr_coeff > 1 ||
asymmetric_scenario = (bfqq->wr_coeff > 1 &&
bfqd->wr_busy_queues < bfqd->busy_queues) ||
!bfq_symmetric_scenario(bfqd);
/*