pinctrl: sprd: Add of_node_put() before return to prevent memory leak

Each iteration of for_each_child_of_node puts the previous node, but in
the case of a return from the middle of the loop, there is no put, thus
causing a memory leak. Hence add an of_node_put before the return in
two places.
Issue found with Coccinelle.

Signed-off-by: Nishka Dasgupta <nishkadg.linux@gmail.com>
Link: https://lore.kernel.org/r/20190808074329.15579-1-nishkadg.linux@gmail.com
Reviewed-by: Baolin Wang <baolin.wang@linaro.org>
Signed-off-by: Linus Walleij <linus.walleij@linaro.org>
This commit is contained in:
Nishka Dasgupta 2019-08-08 13:13:29 +05:30 committed by Linus Walleij
parent 474137c911
commit 5a6bc29032
1 changed files with 7 additions and 2 deletions

View File

@ -925,8 +925,10 @@ static int sprd_pinctrl_parse_dt(struct sprd_pinctrl *sprd_pctl)
for_each_child_of_node(np, child) {
ret = sprd_pinctrl_parse_groups(child, sprd_pctl, grp);
if (ret)
if (ret) {
of_node_put(child);
return ret;
}
*temp++ = grp->name;
grp++;
@ -935,8 +937,11 @@ static int sprd_pinctrl_parse_dt(struct sprd_pinctrl *sprd_pctl)
for_each_child_of_node(child, sub_child) {
ret = sprd_pinctrl_parse_groups(sub_child,
sprd_pctl, grp);
if (ret)
if (ret) {
of_node_put(sub_child);
of_node_put(child);
return ret;
}
*temp++ = grp->name;
grp++;