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hexdump: avoid warning in test function

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The test_data_1_le[] array is a const array of const char *.  To avoid
dropping any const information, we need to use "const char * const *",
not just "const char **".

I'm not sure why the different test arrays end up having different
const'ness, but let's make the pointer we use to traverse them as const
as possible, since we modify neither the array of pointers _or_ the
pointers we find in the array.

Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
This commit is contained in:
Linus Torvalds 2015-04-19 13:48:40 -07:00
parent 8b01fc86b9
commit 17974c054d
1 changed files with 1 additions and 1 deletions
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lib/test-hexdump.c
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@ -48,7 +48,7 @@ static void __init test_hexdump(size_t len, int rowsize, int groupsize,
char test[32 * 3 + 2 + 32 + 1];
char real[32 * 3 + 2 + 32 + 1];
char *p;
const char **result;
const char * const *result;
size_t l = len;
int gs = groupsize, rs = rowsize;
unsigned int i;